안녕하세용 $$f(x)=x^2$$
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
add $a$ squared and $b$ squared to get $c$ squared.
Or, using a more mathematical approach; $c^{2}=a^{2}+b^{2}$
$\mu,M$
$\heartsuit$
$\lim_{n \to \infty}$
winner
안녕하세용 $$f(x)=x^2$$
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
add $a$ squared and $b$ squared to get $c$ squared.
Or, using a more mathematical approach; $c^{2}=a^{2}+b^{2}$
$\mu,M$
$\heartsuit$
$\lim_{n \to \infty}$